【问题描述】设计一个算法判别一个算术表达式的圆括号是否正确配对【输入形式】一个以@为结尾的算术表达式【输出形式】若配对，则输出圆括号的对数；否则输出no 【样例输入】(a+b)/(c+d)@

```pythona=input('')b=[]c=0for i in a:b.append(i)d=int(len(b))for i in range(d) :if b[i]=='(' :for j in range (i+1,d):if b[j] == ')':c += 1...

Chloemxc

4246人浏览 · 2020-01-31 11:15:16

Chloemxc · 2020-01-31 11:15:16 发布


```python
a=input('')
b=[]
c=0
for i in a:
    b.append(i)
d=int(len(b))
for i in range(d) :
    if b[i]=='(' :
        for j in range (i+1,d):
            if b[j] == ')':
                c += 1
                b[j]='s'
                b[i]='s'
                break
    elif b[i]=='@': break
    else :
        pass
v=True
for i in range(d) :
    if b[i] == '(' or b[i] == ')':
        print("no")
        v=False
        break
if v==True:
    print(c)