python常用（ＲＳＡ）

python1.十进制转换为ASCLL值已知十进制为：55,56,54,79,115,69,114,116,107,49,50a = [55,56,54,79,115,69,114,116,107,49,50]c=“”for i in a:b = chr(i)c = c + bprint(c)结果为 786OsErtk122.将字符串转换为数组（数）s = "\x35\x35\x2c\x35\x

JOKER-LE

4622人浏览 · 2022-02-24 20:38:44

JOKER-LE · 2022-02-24 20:38:44 发布

python

1.十进制转换为ASCLL值

已知十进制为：55,56,54,79,115,69,114,116,107,49,50

a = [55,56,54,79,115,69,114,116,107,49,50]
c=“”
for i in a:
	b = chr(i)
	c = c + b
print(c)
结果为 786OsErtk12

2.将字符串转换为数组（数）

s = "\x35\x35\x2c\x35\x36\x2c\x35\x34\x2c\x37\x39\x2c\x31\x31\x35\x2c\x36\x39\x2c\x31\x31\x34\x2c\x31\x31\x36\x2c\x31\x30\x37\x2c\x34\x39\x2c\x35\x30"
print(s)
结果为 55,56,54,79,115,69,114,116,107,49,50

3.ASCLL编码转换

/119/101/108/99/111/109/101/116/111/97/116/116/97/99/107/97/110/100/100/101/102/101/110/99/101/119/111/114/108/100

import re
 r="/119/101/108/99/111/109/101/116/111/97/116/116/97/99/107/97/110/100/100/101/102/101/110/99/101/119/111/114/108/100"
   
r=re.split("/",r)
flag=""
for i in range(1,len(r)):
    flag=flag+chr(int(r[i]))
    
print (flag)

结果：welcometoattackanddefenceworld

4.二进制转字符串

import re
a='01100110011011000110000101100111011110110100011001110101010011100101111101100111011010010100011001111101'
    b=re.findall(r'.{8}',a)
    flag=''
    for i in b:
        flag += chr(int(i,2))
    print(flag)